benraden benraden

10-06-2018
Mathematics

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What’s the answer in this problem I’m stuck and can’t go forward

Whats the answer in this problem Im stuck and cant go forward class=

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jessecnphillips jessecnphillips

10-06-2018

Subtract m<2 from KJL to find m<1
55-27=28 degrees

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10-06-2018

m∠KJL-m∠2=m∠1
substitute,
55-27= 28
so m∠1 is 28°

Answer Link

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