sheb2347
sheb2347 sheb2347
  • 11-09-2018
  • Mathematics
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Please help!! 10 points available!

Please help 10 points available class=

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gmany
gmany gmany
  • 18-09-2018

[tex]sine=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{8}{10}=\dfrac{4}{5}\to\boxed{B.}[/tex]

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