m([tex]Ca Cl_{2} [/tex])=535 g
m(Cl)=?
The molar mass of [tex]CaCl_{2} [/tex] = 40.08 + 2 * 35.45 = 110.98
The atomic mass of Cl: 35.45 ( you can see it in the Periodic table)
110.98 g [tex]CaCl_{2} [/tex]- 35.45 * 2 g Cl
535 g [tex]CaCl_{2} [/tex] - x g Cl
Proportion:
110.98 : 535 = (35,45 * 2) : x
x = 535 * 35.45 * 2 / 110.98 = 37,931.5/110.98 = 341.79 g
Answer: m(Cl)=341.79 g
