Respuesta :

caylus
Hello,

We suppose x≠2 and x≠1.

x/(x-2)+(x-1)(x+1)=-1
==> (x²+x-(x²-x-2x+2))/(x²-x-2)=-1
==>4x-2=-x²+x+2
==>x²+3x-4=0
==>(x+4)(x-1)=0
Sol ={-4,1} which are different of the excluded values.