Answer:
[tex]\frac{-1}{13x}[/tex]
Step-by-step explanation:
[tex]\frac{2x-32}{16x}[/tex] = [tex]\frac{2x}{16x}[/tex] — [tex]\frac{32}{16x}[/tex]
[tex]\frac{2x-2x}{16x-2x}[/tex] = [tex]\frac{1}{14x}[/tex]
[tex]\frac{32/16}{16x/16}[/tex] = [tex]\frac{2}{x}[/tex]
[tex]\frac{-1}{13x}[/tex]
