Respuesta :

Space

Answer:

There are 0.00390 moles of Barium in 2.35 × 10²¹ atoms of Ba.

General Formulas and Concepts:
Stoichiometry

  • Mole ratio
  • Avogadro's Number: 6.023 × 10²³ atoms/moles/molecules/formula units/etc.
  • Dimensional analysis

Explanation:

Step 1: Define

Identify.

2.35 × 10²¹ atoms Ba

Step 2: Convert

  1. [Dimensional Analysis] Set up:                                                                    [tex]\displaystyle 2.35 \cdot 10^{21} \ \text{atoms Ba} \bigg( \frac{1 \ \text{mol Ba}}{6.022 \cdot 10^{23} \ \text{atoms Ba}} \bigg)[/tex]
  2. [Dimensional Analysis] Evaluate:                                                                [tex]\displaystyle \displaystyle 2.35 \cdot 10^{21} \ \text{atoms Ba} \bigg( \frac{1 \ \text{mol Ba}}{6.022 \cdot 10^{23} \ \text{atoms Ba}} \bigg) = 0.003902[/tex]
  3. [Sig Figs] Round:                                                                                           [tex]\displaystyle \displaystyle 2.35 \cdot 10^{21} \ \text{atoms Ba} \bigg( \frac{1 \ \text{mol Ba}}{6.022 \cdot 10^{23} \ \text{atoms Ba}} \bigg) \approx 0.00390[/tex]

Topic: AP Chemistry

Unit: Stoichiometry

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