jaylal5080 jaylal5080

12-03-2020
Mathematics

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Solve systems of equations

-x^2-4x+y=0
-x^2+9x+y+13=0

Respuesta :

dannielle dannielle

12-03-2020

Answer:

I solve it by substitution

y=x^2+4x

-x^2+9x+(x^2+4x)+13=0

13x+13=0

13x=-13

x= -13/13

x= -1

y=x^2+4x=1-4

y= -3

Step-by-step explanation:

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