blakebrown244
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  • 12-04-2020
  • Mathematics
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X^3+7x^2-5x-35 factor completely

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gmany
gmany gmany
  • 12-04-2020

Answer:

[tex]\huge\boxed{x^3+7x^2-5x-35=(x+7)(x-\sqrt5)(x+\sqrt5)}[/tex]

Step-by-step explanation:

[tex]x^3+7x^2-5x-35=x^2(x+7)-5(x+7)=(x+7)(x^2-5)\\\\=(x+7)(x^2-(\sqrt5)^2)=(x+7)(x-\sqrt5)(x+\sqrt5)\\\\\text{Used:}\\\\\text{the distributive property:}\ a(b+c)=ab+ac\\\\a^2-b^2=(a-b)(a+b)\\\\(\sqrt{a})^2=a,\ \text{for}\ a\geq0[/tex]

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