Mirandbonyhipent
Mirandbonyhipent
10-08-2016
Mathematics
contestada
divide m^2 n^2/p^3 by mp/n^2
Respuesta :
Panoyin
Panoyin
10-08-2016
[tex]\frac{m^{2}n^{2}}{p^{3}} \div \frac{mp}{n^{2}}[/tex]
[tex]\frac{m^{2}n^{2}}{p^{3}} \times \frac{n^{2}}{mp}[/tex]
[tex]\frac{m^{2}n^{4}}{mp^{4}}[/tex]
[tex]\frac{mn^{4}}{p^{4}}[/tex]
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