mthiam2022 mthiam2022
  • 11-02-2021
  • Chemistry
contestada

How many joules of heat energy are absorbed when 80.0 g of water are heated from 10.0°C to 50.0°C? *

Respuesta :

timo86
timo86 timo86
  • 15-02-2021

Answer:

13440 J

Explanation:

c ≈ 4200 J / (kg * °C)

m = 80 g = 0,08 kg

[tex]t_{1}[/tex] = 10 °C

[tex]t_{2}[/tex] = 50 °C

The formula is: Q = c * m * ([tex]t_{2} - t_{1}[/tex])

Calculating:

Q = 4200 * 0,08 * (50 - 10) = 13440 (J)

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