[tex]8x + 3y = 70[/tex]
with given condition where y = 2.
Therefore, substitute the value of y in the equation.
[tex]8x + 3(2) = 70 \\ 8x + 6 = 70[/tex]
[tex]8x = 70 - 6 \\ 8x = 64 \\ x = \frac{64}{8} \longrightarrow \frac{8}{1} \\ x = 8[/tex]
[tex]8x + 3y = 70 \\ 8(8) + 3(2) = 70 \\ 64 + 6 = 70 \\ 70 = 70[/tex]
Hence, the equation is true for x = 8 and y = 2.
[tex] \large{x = 8}[/tex]