[tex]f(1) = -6[/tex]
Given:
[tex]f(x) = \begin{cases} -(x +5)^2 &\text{for} &x \leqslant -3 \\ -2x -4 &\text{for} &-3 < x \leqslant 1 \\ 5 &\text{for} &x > 1 \end{cases}[/tex]
[tex]f(1) = -2x -4 \space , \space x = 1 \\ f(1) = -2(1) -4 \\ f(1) = -2 -4 \\ f(1) = -6[/tex]
