Mayarios Mayarios
  • 11-12-2021
  • Mathematics
contestada

a √(x^2-n/m)= a^2/b make x subject

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loneguy
loneguy loneguy
  • 11-12-2021

[tex]\sqrt{x^2 -\dfrac nm} = \dfrac{a^2}b\\\\\implies x^2 - \dfrac nm = \dfrac{a^4}{b^2}\\\\\implies x^2 = \dfrac{a^4}{b^2} + \dfrac nm}\\\\\implies x = \pm \sqrt{ \dfrac{a^4}{b^2} + \dfrac nm}}[/tex]

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