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  • 10-04-2022
  • Chemistry
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How many atoms in total are present in sucrose C12H2011 weighs 1.4 mg

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Festus19
Festus19 Festus19
  • 10-04-2022

Answer:

2.46×10²¹atoms

Explanation:

[tex]molar \: mass \: of \: the \: sucrose = 12(12) + 22(1) + 11(16) \\ = 144 + 22 + 176 \\ = 342g {mol}^{ - 1} \\ mole = \frac{1.4 \times {10}^{ - 3} }{342} \\ = 4.09 \times {10}^{ - 6} \\ number \: of \: atoms = 4.09 \times {10}^{ - 6} \times 6.022 \times {10}^{23} \\ = 2.46 \times {10}^{21} atoms[/tex]

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