Respuesta :

konrad509

[tex]B\cap C=\emptyset\\A\cup(B\cap C)=\{a,b,c,d,e,f\}\\A\cup B=\{a,b,c,d,e,f,g\}\\A\cup C=\{a,b,c,d,e,f,i,o,u\}\\(A \cup B)\cap (A \cup C)=\{a,b,c,d,e,f\}[/tex]

As you can see [tex]A\cup(B\cap C)=(A \cup B)\cap (A \cup C)[/tex]