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Question 4(Multiple Choice Worth 1 points)
(06.05 MC)
Given the functions k(x) = 2x² - 5 and p(x) = x - 3, find (k. p)(x).
(kop)(x) = 2x² - 6x + 4
(kop)(x) = 2x² - 12x + 13
(kop)(x) = 2x² - 12x + 18
(kop)(x) = 2x² - 8

Respuesta :

fieryanswererft

Answer:

2x² - 12x + 13

Step-by-step explanation:

Given following:

  • k(x) = 2x² - 5
  • p(x) = x - 3

Start solving from right to left across the function.

Steps:

  • k[p(x)]
  • k[x - 3]
  • 2(x - 3)² - 5
  • 2(x² - 6x + 9) - 5
  • 2x² - 12x + 18 - 5
  • 2x² - 12x + 13
G00sequack

Answer:

2x² - 12x + 13

Step-by-step explanation:

Steps:

k[p(x)]

k[x - 3]

2(x - 3)² - 5

2(x² - 6x + 9) - 5

2x² - 12x + 18 - 5

2x² - 12x + 13             pls brainlest