Respuesta :

LammettHash

[tex]\displaystyle \int_0^2 \int_0^{2-x} \int_0^{2-x-y} dz \, dy \, dx = \int_0^2 \int_0^{2-x} (2-x-y) \, dy \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^2 (x-2)^2 \, dx = \boxed{\frac43}[/tex]