jdcash7999 jdcash7999

10-11-2017
Chemistry

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If you had excess chlorine, how many moles of of aluminum chloride could be produced from 28.0 g of aluminum?

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Kalahira Kalahira

21-11-2017

Answer: 2Al(s) + 3Cl2(g) ---> 2AlCl3(s) Always work in moles moles = mass of substane / molar mass 2Al (s) + 3Cl (g) --> 2AlCl3 (s) moles Al = 23.0 g / 26.98 g/mol = 0.852 moles Al

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