Two buses leave a station at the same time and travel in opposite directions. one bus travels 14 /mih faster than the other. if the two buses are 496mi apart after 4 hours, what is the rate of each bus?
let the speed of the slower bus be equal to x miles per hour let the speed of the faster bus be equal to x+14 miles per hour after every hour they would be a further 2x+14 miles apart from eachother therefore after 4 hours they would be 4(2x+14) = 8x + 56 miles away from eachother since we know exactly how many miles this is we can solve for x 8x + 56 = 496 8x = 440 x = 55 x + 14 = 69 therefore, the speed of the slower bus is 55 mph whereas the speed of the faster bus is 69 mph
