Respuesta :

shownubear1992

Answer:

d = [tex]2\sqrt{29}[/tex]

Step-by-step explanation:

[tex]d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(0-4)^2+(0-10)^2}\\d= \sqrt{(-4)^2+(-10)^2}\\d= \sqrt{16+100}\\d= \sqrt{116}\\d=2 \sqrt{29}[/tex]

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